Do the units of $G/c^4$ make intuitive sense? In classical Newtonian mechanics, gravity is explained by: 
$$F=G \frac {Mm} {r^2}$$
Where $F$ is the force due to gravitation, $M$ and $m$ are the masses of the two bodies in question, $r$ is the distance between them, and $G$ is the Universal Gravitation Constant as defined by Newton. In SI units, $G$ is measured in $N\frac {m^2}{kg^2}$.
However, Einstein later discovered that $m$ (at least at rest) was equal to $E/c^2$, where $E$ is energy (in this case, the confined energy inherent to rest mass) and $c$ is the speed of light. Plugging this into the Newtonian Gravitation Equation (completely unorthodox, I know) yields 
$$
F=G* \frac {\frac E {c^2} \frac e {c^2}} {r^2}
$$$$
F= \frac G{c^4} \frac {Ee}{r^2}
$$$$
F=\bar G \frac {Ee}{r^2}
$$
The new quantity $G/c^4=\bar G$ has SI units of $N \frac {m^2} {J^2}$ which after a little math reduces to $m/J$ as $Nm=J$. Thanks to General Relativity, this reduction feels perfectly intuitive - meters of distortion per joule of energy. 
However, General Relativity replaced Newtonian Gravity, and I don't actually have any real intuitions for General Relativity, so I have two questions: Is "meters of distortion per joule of energy" a reasonable way of thinking about the General Relativity concept of gravity, and does my derivation of $\bar G$ make any sense? 
 A: This probably isn't the best way of thinking about things, for several reasons:


*

*In GR, the curvature of spacetime is not determined by the amount of matter/energy present (in Joules), but by the density of the energy (in Joules per $\text{m}^3$.)  

*In fact, spacetime can be distorted in GR in a region not containing any matter or energy at all, as has been shown 4.9 times by LIGO (to date).  Thinking of distortion as inherently produced by nearby energy is liable to lead you astray.  (And if you try to think of the distortion on Earth as being related to the mass/energy of the black holes in a LIGO event, you would conclude that the distortion should be gargantuan.)

*"Meters of distortion" is not the right way to think about the distortion of spacetime.  For example, in a gravitational wave event, if we have two objects a distance $x$ apart, then the distance between them changes by an amount $\Delta x$ that's proportional to $x$.  The quantity $\Delta x/x$ is called the gravitational strain, and it's dimensionless.
To me, your interpretation of "meters of distortion per joule of energy" sounds a bit like you're taking the rubber-sheet analogy too seriously.  It's a fine picture for thinking about what's going on in a quantitative sense, but it fails pretty rapidly if you try to go beyond that. 
A: Congratulations! You have independently (partially) rediscovered Einstein's theory of general relativity.
The action of general relativity (with cosmological constant $\Lambda$) is
$$
S = \frac{c^4}{8\pi G}\int \varepsilon_{abcd}e^a e^b (d\omega^{cd} + \eta_{lm}\omega^{cl}\omega^{md} + \frac{\Lambda}{6}e^c e^d).
$$
Your $\frac{G}{c^4}$ is only $8\pi$ away from the (inversed) coefficient in front of Einstein's action. The differential forms $e$ and $\omega$ in the action are just some minute technicalities. 
Similarly, the same coefficient is moved to the right hand side of Einstein's field equation
$$
R_{\mu\nu}-\frac {1}{2}g_{\mu\nu}R+g_{\mu\nu}\Lambda=\frac {8\pi G}{c^4}T_{\mu\nu},
$$
where $T_{\mu\nu}$ is the energy-momentum tensor, which echoes your observation. 
A: Absolutely, this is a great way to remember and think about G.  For example, in GR the Schwarzschild radius of a black hole is:
$$
R_{Schwarzchild}=2\frac{G}{c^2}M \quad (=3 \ km \ for \ our \ Sun)
$$
Many physicists remember $\frac{G}{c^2}=1.5 \ km \ per \ solar \ mass$, and this is what they use to do astrophysics calculations.   Particle physics theorists remember $\frac{G}{c^4}=10^{-39} \ Fermi \ per \ GeV$  Actually nobody writes the c's until they have to in their final answers to get the dimensions correct. Almost never does someone have to look up and use $G=6.67 \ 10^{-11} \ \frac{m^3}{kg \ sec^2}$.
A: $\frac{G}{c^4}$ is the inverse upper limit of the classical gravitational force. That is it's true interpretation. 
A: The intuitive interpretation of the units of $G/c^4$ is “Riemannian curvature per energy density”, as follows from the Einstein field equations. Riemannian curvature is measured in units of inverse-meters-squared, and energy density is measured in units of Joules per cubic meter. The ratio of these is meters per Joule.
