In compton effect, the x-ray photon striking the electron imparts some of its energy to the electron and a photon of lesser frequency is scattered. Also, to conserve the angular momentum(i don't know too much about it), whole of the energy of photon can't be absorbed by the electron. However, in einstein's photoelectric equation, it is said that the whole energy 'hf' is used( some part in pulling it outside the metal surface and the remaining in increasing its kinetic energy). Then, the whole explanation must be wrong of photoelectric effect as whole energy of photon can't be absorbed by an electron. Please notify me wherever I m going wrong.

  • $\begingroup$ In the photoelectric effect the chunk of metal that the photoelectron is ejected from can mop up any stray momentum. In Compton scattering the electron is isolated so this can't happen. $\endgroup$ – John Rennie Oct 25 '17 at 12:24
  • $\begingroup$ But the book i m reading has written that the electron is loosely bounded. $\endgroup$ – Gurbir Singh Oct 25 '17 at 12:25
  • $\begingroup$ In the photoelectric effect, the electron is bound to an atom. In the compton scattering, the electron is considered to be free. $\endgroup$ – Andrei Geanta Oct 25 '17 at 12:27
  • $\begingroup$ But it should not matter if we are giving enough energized photons. $\endgroup$ – Gurbir Singh Oct 25 '17 at 12:28
  • $\begingroup$ What book are you reading? $\endgroup$ – Andrei Geanta Oct 25 '17 at 12:38

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