# What does Quantum Spin Cause? [duplicate]

How do particles with different Quantum Spin Numbers interact differently with other matter? What does spin cause? I understand that electrons etc act as if they are spinning my emitting a magnetic field (I think?) but what does the spin value represent? Does it represent the rate at which a particle would have to spin at to emit an electromagnetic field of x size? If so, what is the multiplier?

(I am new to particle/quantum physics [I am just researching it for fun {I am in 8th Grade}])

## marked as duplicate by stafusa, John Rennie, Qmechanic♦Oct 6 '17 at 14:32

• Spins don't indicate that particles are spinning. That's a horrible misconception. Spin is an intrinsic property of a particle. When particle reactions take place, then several conservation principles are followed, like Lepton number conservation, Barton number conservation, Hypercharge conservation, Isospin conservation, Spin Quantum Number conservation, and so on. The topic is a very broad one and it's difficult for us to teach here. Please do some good research. You may refer to books like "Introduction to Elementary Particle Physics" by D. J. Griffiths for introduction and further reading – Wrichik Basu Oct 5 '17 at 21:07
• Related: physics.stackexchange.com/q/1/2451 , physics.stackexchange.com/q/822/2451 and links therein. – Qmechanic Oct 5 '17 at 21:21
• @WrichikBasu: I think an Intro to QM text might be more appropriate than particle physics text – Kyle Kanos Oct 6 '17 at 9:58

The spin of particle can roughly be physically thought of as the magnetic moment of the particle (or the strength of the magnetic field generated by the particle). For example, a spin-$0$ particle has no magnetic moment, and a spin-$1/2$ particle has half the magnetic moment of a spin-$1$ particle. Experimentally, what this means is that if I shoot a particle while applying a magnetic field, the particle will deflect a certain amount based on its spin. The greater the spin, the more it gets deflected.
Actually, the situation is a little bit more complicated than this due to quantum mechanical effects; there is something called the Lande g-factor which means that a spin-$1$ particle might not necessarily have twice the response under a magnetic field of that of a spin-$1/2$ particle. This, in part, has to do with the fact that the particle (eg the electron) is not actually spinning (even though we call it spin) and there is deep and complicated physics that goes into this.
• More spin leads to more deflection. $0$ spin, for example, means it isn't affected at all. As I mentioned in the answer, this entire description should not be taken super literally, but as a rough description of what happens. – Aaron Oct 6 '17 at 15:41