-1
$\begingroup$

We know that we have 7 fundamental quantities (all scalars) and length is one of them. I classify velocity as a derived quantity. What about a position displacement vector? How do I classify displacement vector. Is it fundamental or derived quantity?

$\endgroup$
1
$\begingroup$

It depends on the convention what to use as a fundamental quantity, but if you refer to SI it is:

$$ [D] = [\epsilon_0]\cdot [E] = [\epsilon_0]\cdot [F]/[Q] = \mathrm{\frac{A^2\, s^4}{kg\, m^3}\cdot \frac{kg\, m}{s^2}\cdot \left(A\, s\right)^{-1} = \frac{A\, s}{m^2}}. $$

  • a fundamental quantity if you refer to a position displacement, because it is a length,

$$ [r] = \mathrm m. $$

$\endgroup$
  • $\begingroup$ I am referring to a position displacement. Because I asked a question because I saw a question asking 7 fundamental quantities are scalars or vectors. The answer was scalar. So I was a little bit confused that position displacement is a vector not scalar. $\endgroup$ – ofenerci Oct 3 '17 at 10:19
  • $\begingroup$ Could you link the question you have just cited? @ofenerci $\endgroup$ – Annibale Oct 3 '17 at 15:01
  • $\begingroup$ Length is a scalar coming from this post physics.stackexchange.com/questions/67375/… $\endgroup$ – ofenerci Oct 3 '17 at 15:55

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.