Will a particle still be in a superposition state if unobserved from only the perspective of one observer? In this scenario let us take a particle that can have either spin up or spin down. Let's say that observer 1 observed the particle's spin to be down. But observer 2 hasn't observed it yet. So, then would the wave-function have collapsed from his/her perspective? Would the particle be in a superposition of an observed/unobserved state (if there is such a thing)? Also, how would a similar scenario play out when there is a pair of entangled particles?  
 A: This question has no answer (or rather it has multiple speculative answers), and all comes down to quantum interpretation.
I don't think it's controversial to say that the majority preference (if one makes such assumptions) is to believe that no, the particle will not still be in superposition to one observer once observed by another, as its macroscopic interactions (e.g. measurement) have caused the particle to decohere absolutely.
There are however interpretations such as qbism (quantum Bayesian) that through taking a Bayesian approach assume all states are knowledge based, so for instance one can imagine that by observing the spin of a particle, to an external non-observer you are now in a superposition along with the particle---this secondary person still has no further knowledge of the system.
There are also interpretations where this question isn't even considered relevant or it's just unclear what assumption one should form.
Sorry if this isn't satisfactory; that's just how it is. If you'd like any more information on a specific interpretation (or any other follow-up), let me know and I'll try to expand this answer accordingly.
