I have a question asking to find the energy of a photon emitted from mater of temperature $T$. If the question had asked frequency, it would have clearly been that $E_{photon}=h\cdot f$. I do know that classically, the energy of an oscillator is $E = K_{b} \cdot T$. Is it okay to use this formula for this question?
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2$\begingroup$ To me it sounds like it wants you to assume blackbody radiation $\endgroup$– Señor OCommented Sep 23, 2017 at 21:21
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$\begingroup$ Is there a way to relate the frequency of an emitted photon to the temperature of the mater it was emitted from? $\endgroup$– Space20Commented Sep 23, 2017 at 21:56
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1 Answer
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According to the physics of blackbody radiation, Wien's displacement law states that the peak (i.e. most probable) wavelength of radiation from a perfect blackbody at temperature $T$ is given by
$\lambda_{peak} = \frac{2.898 ×10^{-3} m⋅K}{T}$
From the wavelength you can, of course, calculate the frequency and therefore the energy.
I am making an assumption that this probably wants you to make the approximation that the object is close to a perfect blackbody, and that you've probably measured more than just "one photon" so you actually know the most common photon wavelength coming out.
