# Why are photons not involved in $\beta -$ decay?

Theory of $\beta -$ emission exclusively considers participation of one $W -$ boson, one electron and one electron-antineutrino, but no photons. However Maxwell's electrodynamics require that during any change of an electromagnetic field, EM-radiation (photons) must be emitted. Spontaneous separation of two oppositely charged particles generates a variable electric dipole field which should emit EM-radiation. Moreover, as the emitted electron is strongly decelerated in the Coulomb field this also should generate EM-radiation. However, spin angular momentum conservation would require pairwise emission of photons with mutually opposed spin (sum $+1 - 1 = 0$). To my knowledge such EM-radiation has never been reported or predicted.

• Does the resultant nuclei-electron orbital change count? – honeste_vivere Sep 8 '17 at 17:02