Ball A is thrown upward at the same time as ball B and with half the speed of ball B. a) Will ball A or B hit the ground faster? b) How much higher does B go than A?
This is one of my homework problems. But I'm confused because if the speed of ball B is twice that of ball A's, shouldn't it hit the ground first? However, the answer is that A will hit the ground before B. Why would that be so? I tried to use the displacement formula (for both a) and b)), but I'm not sure if I'm doing it right. I got the equations $x_A = 0 + v_0t - 4.9t^2$ and $x_b = 0 + 2v_0t - 4.9t^2$, but have no idea how to carry on. Also, I feel like I can get b) from the above equations, but how can I do that?