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In diagrams that contain the dashpot symbol, sometimes the mass is attached to the "interior" end of the dashpot, other times the mass is attached to the "base" end.

For example, consider the following diagram (please ignore the equations):

enter image description here

Does it make any difference if the dashpot symbol in the above figure is reflected in the vertical line? If not, which is the conventional orientation to draw the dashpot in?

Thanks.

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  • $\begingroup$ By dashpot, do you mean the symbol below "C"? All you need to solve the problem is the differential equation, i.e the term proportional to the velocity. The picture is irrelevant. $\endgroup$ Sep 1 '12 at 14:18
  • $\begingroup$ @AntillarMaximus Yes I mean that symbol. Oh I'm not trying to solve the problem (the picture was googled up). My question is about the symbol because I've seen it both ways in the notes I was given and I want to know what's the essential difference between the two differnt representations (orientated two different ways). $\endgroup$
    – Ryan G
    Sep 1 '12 at 14:25
  • $\begingroup$ You should look for the terms "driven" ,"damped" in the notes. This is what decides the behavior of your oscillator. No matter how the picture is, if your notes say "damped" you will have one form of the equation, if it says "driven" you will have the other form. Are you studying R-C oscillators? $\endgroup$ Sep 1 '12 at 14:34
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    $\begingroup$ @AntillarMaximus I am merely asking about the symbol! Why is it sometimes directed one way and other times directed in the opposite direction? Ignore any perceived physics problem! $\endgroup$
    – Ryan G
    Sep 1 '12 at 14:59
  • $\begingroup$ It depends on the whim of the author I suppose. $\endgroup$ Sep 1 '12 at 15:59
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The direction is absolutely irrelevant, it can be either way. Just imagine that damper, a kind of piston and how you stretch and contract it. Thus you should intuitively feel why the orientation doesn't matter. Below is a bit more rigorous explanation:

The power required by an external force to move a damper doesn't depend on the damper's orientation, only on the relative speed of its parts. Or probably the relative position of it's parts. And distance and relative speed don't depend on the orientation, that's just the basic property of our usual spacetime.

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  • $\begingroup$ Yes I didn't think the orientation would be relevant to the damping problems, but I sincerely thought that there would be a standard convention to draw these things. Like the "interior" end always facing the mass, or or "base" end always facing the mass. $\endgroup$
    – Ryan G
    Sep 2 '12 at 9:09

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