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We consider that the satellite has time period equal to earth's rotational period, because of equal magnitude of orbital velocity, if that is so, it's at rest relative to earth's rotational motion which carries along the atmosphere at the same velocity so there must have been no air resistance being acted upon the geostationary satellite.

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closed as unclear what you're asking by John Rennie, M. Enns, Jon Custer, honeste_vivere, Qmechanic Aug 25 '17 at 16:45

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

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    $\begingroup$ It is not clear what you are asking or how your question in the title relates to the text. $\endgroup$ – user1583209 Aug 25 '17 at 9:31
  • $\begingroup$ In context to geostationary satellites, they have velocity equal to the velocity of earth rotating about it's own axis and since earth holds the atmosphere it should too have velocity equal to that of earth while roatating. If it was so how can the geo stationary satellite have face any air resistance even if there is very lowly densed atmosphere at that height? For it to slow down? $\endgroup$ – sopnil koirala Aug 25 '17 at 9:47
  • $\begingroup$ Are you thinking of elliptical orbits? $\endgroup$ – JMac Aug 25 '17 at 10:52
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If the satellite rotates the earth in 24 hours, then it is in a so called geostationary (or geosynchronous) orbit. Such an orbit is circular and has an altitude of nearly 36,000 km above the equator. There is very little atmosphere at that height.

More of an issue is the effects of lunar and solar gravity and the fact that the earth isn't an exact sphere. To counter these effects, orbital corrections are required periodically. The satellites have onboard propulsion systems to achieve this.

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