# Why $c$ as speed of change in gravity [duplicate]

Consider two bodies where say body B is in gravitational field of A Now we move body A with much needed speed so as to produce observable results. Now as I read that this information that A has changed its place travels with speed $c$. My question is: Why $c$? Its value comes from $\mu_0$ and $\varepsilon_0$ which deals with electromagnetism, $c = 1/\sqrt{\mu_0 \varepsilon_0}$ , there can be possibility of some other speed .

Example: when pressure changes at one side of water pipe this "information of change" travels with speed of sound in water This seems confusing. Is there some connection of fields of Gravitation and electromagnetism?

## marked as duplicate by AccidentalFourierTransform, Qmechanic♦Aug 20 '17 at 10:34

• Possible duplicate by OP: Speed of changes in the field – AccidentalFourierTransform Aug 20 '17 at 8:31
• Why the downvote? Not everyone knows relativity. – Pritt Balagopal Aug 20 '17 at 9:49
• Hi Pranjal Rana. Welcome to Phys.SE. Please don't repost a closed question in a new entry. Instead, you are supposed to edit the original question within the original entry. – Qmechanic Aug 20 '17 at 10:36

Electromagnetism is described by the Maxwell equations which have the curious property of having one velocity, $c$, which is everywhere. But these equations do not specify a reference frame. This suggested an ether to which this velocity is relative to. With the Michelson–Morley experiment, this was ruled out. So there is one velocity which is the same in every frame of reference. The consequence is that the addition (and general transformation) of velocities was changed, this is special relativity theory.
General relativity then also described gravity and the gravitational waves that you seem to mean. The only velocity in the theory is $c$, so these also travel with the speed of light because that is an intrinsic property of spacetime.