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While studying the characteristic spectra of x-rays I came across one question that lets me doubt that I have fully understood what is going on.

The $K_{\alpha}$ line is due to inner orbital electrons being ejected from the K-shell of the atoms by the x-ray source. The place is then filled by an electron from the L-shell. Since the energy in the L-shell is higher than in the K-shell, a photon is emitted with the energy $\Delta E=\hbar\omega$. This process corresponds to the $K_{\alpha}$ line. Analogously for the $K_{\beta}$ line.

So from my understanding a $K_{\gamma}$ (and so on) should also exist, but I couldn't find anything about this. Is this simply due to the low probability of this transition so one cannot observe it, because its intensity is lower than the Bremsstrahlungs spectrum?

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  • $\begingroup$ Probably. In energy dispersive x-ray diffraction, I often saw strong $K_\alpha$ peaks. Sometimes significant $K_\beta$ peaks, too, which are generally smaller. Don't recall offhand ever seeing $K_\gamma$. Never thought about it or looked deeply into the matter, though. Just always assumed that the probability of such transitions was relatively low. $\endgroup$ – Samuel Weir Jul 31 '17 at 23:09
  • $\begingroup$ That is basically what I found in text books and online. For example the NIST database doesn't list any $K_{\gamma}$ transition intensities. $\endgroup$ – Timo Aug 1 '17 at 17:06
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Here is a spectrum from a tungsten x-ray tube:

X-ray spectra measured using a CdTe detector with changes in the tube voltage.

One sees the strong W K$_{\alpha 1}$ and K$_{\alpha 2}$ lines. The W K$_{\beta}$ line is also labeled. The K$_{\gamma}$ line is not labeled but visible. Its energy is about 2 keV higher than K$_{\beta}.$ These transitions involve the N shell.

One sees why K$_{\gamma}$ is not usually mentioned. In electron-induced x-ray spectra, it is weaker than the Bremsstrahlung background. If one wants to study the spectrum (for example to study the $4p$ bands of iron or copper), one uses x-ray excitation.

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