I think I understand the idea of latent heat, but the wording (or lack thereof) of practice problems instantly makes me think that more information should be given. Either that, or I'm not understanding it correctly.

Textbooks often will ask a question like "A 100 watt heater is used to melt ice. After 60 seconds, 0.02 kg of ice has melted. Find the latent heat of fusion for ice."

When I imagine ice, I imagine something that is below zero degrees Celsius. Look at this nice graph that I made showing the temperature change of a material (H2O, for example) over time:

enter image description here

I want to understand that latent heat of fusion is the energy required to get from point B to point C on my graph. Is that correct?

The wording of most questions/explanations I see make me think that it is the energy required to get from point A (an arbitrary point below the melting point) to point C. For example, in the practice problem I provided earlier, it doesn't mention the original starting temperature of the ice.

In order to do experiments like this to determine the latent heat of fusion for a material (ice, for example), shouldn't the ice be just a tiny fraction of a degree off of the melting point? Or, ideally, just at the melting point?

  • $\begingroup$ This can be in a situation where there is a water/ice equilibrium. $\endgroup$
    – user137289
    Jul 2, 2017 at 13:12

1 Answer 1


The latent heat of fusion is the energy required to go from point B to point C. (or vice versa)

Generally in these questions if no temperature is given, you assume it's known the ice is perfectly at it's melting point (point B).

The point of these questions is to understand what the latent heat of fusion is and what it does. It is an energy barrier between the phase changes.

In reality; your ice probably wont be perfectly at it's melting point (and phase changes are actually more complicated than that anyways; especially going from liquid to solid). So yes, there would also be some required heat to get it to the melting temperature.

As long as you knew the properties of the ice and it's temperature, you could determine that energy as well. Since you are not given that information; it seems the problems are to illustrate that fusion itself requires energy, or "latent heat" (because the temperature does not change during this heating).

If you are just being introduced to all this, I think it's great you have this question. You've recognized that the textbook is making an assumption and is not clearly stating it; but I think it's safe to assume they are not trying to perfectly model reality, but are just trying to illustrate an example.

  • $\begingroup$ It is actually pretty straightforward to get ice exactly at its melting point. Heat the ice until is just starts to melt, stop heating and drain off as much of the water produced as you can. Now you messure the mass of ice of unmelted ice. You are now ready start your experiment with the ice exactly at its melting point. If you use a very large block of ice, you should be able to make the error due to having some liquid water present at the start of the experiment fairly small. This is possible precisely because of the latent heat and the plateau in the temperature/time graph in the question. $\endgroup$ Jul 2, 2017 at 13:48
  • $\begingroup$ @BySymmetry That still doesn't really work; you would need some method to uniformly heat the ice; therefore a larger block would actually be worse as the insides would be cooler than the melting point. So you have competing errors; a fairly small system would probably be approximately perfect. I'm sure you could come up with methods for getting perfect temperature ice; but it's still not quite that simple; and really isn't the point of my answer; which is that the question is more about theory than reality. $\endgroup$
    – JMac
    Jul 2, 2017 at 13:52
  • $\begingroup$ Great! That makes perfect sense. That's the way I was understanding it, but my textbooks didn't make it clear enough. Thanks! $\endgroup$
    – Jumpman
    Jul 2, 2017 at 23:21

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.