The entropy of a Schwarzschild black hole is proportional to $m^2$ where $m$ is the mass of the black hole. The volume of the black hole would be proportional to $m^3$ and the area would be proportional to $m^2$. Thus, with an increasing mass, the ratio of the entropy to volume would keep on decreasing but the ratio of the entropy to the area remains constant - always.
If we consider the entropy to be a direct measure of information then information per unit volume keeps on decreasing with increasing information but the information per unit area remains constant.
In my very limited knowledge about holography, I think this observation is one of the basic ideas behind holography: although we can have a large volume, we don't have enough information inside it if we expect every unit of volume to have some information on its own. Rather, the information seems to live on the surface where the larger the area, the larger the entropy (and in the same proportion).
But below a certain value of mass, the ratio of entropy to volume would become greater than the ratio of entropy to area. I am not sure why but this seems weird in some sense. I understand that the ratio of entropy to area is still constant but if the information really lives on the surface then the fact that the information is more dense in the bulk than it is on the surface seems awkward.
Is this a legitimate concern or there is nothing awkward going on here?
Edit Owing to some discussion in the comments, I would like to clarify that I don't think that raising the issue that area and volume have different units has any curcial relevance here. I work in a system where $l_P=1$. Just like in relativity we can very well add $t$ to $x$ and so on by setting $c=1$, we can compare $A$ and $V$ as the same dimensional quantities by setting $l_P=1$. In relativity $x/t$ is dimensionless owing to setting $c=1$ - not just setting $c$ as the reference quantity for speed but setting $c$ to $1$ - a dimensionless constant. Similarly, if we set $l_P=1$, we can very well have $A/V$ dimensionless.