# Can an object be perfectly flat? [duplicate]

I ask myself this question from a microscopic point. I assume that at our scale it's pretty easy to say that an object is flat or not.

You need to imagine that we are at the top layer of a material. Above there is air and below the tube there is the rest of the material. The tube is just the top layer of the material with radius $\delta$, considered as the radius of a nucleus !

My question is : If we define this material as flat, does it mean that the top layer is perfectly aligned (Fig 1) or can we consider some little error $\varepsilon > 0$ (Fig 2) ? $\varepsilon$ is defined as the difference between the center of 2 nucleus  • So long as microscopic fundamental particles have dimension, is anything truly flat? I think it depends on how you define flat. If you have a sheet of atoms, 1 atom thick, each atom still have a radius which you called $\delta$. So does this make the sheet a box of dimension $length*width*\delta$? For something to be truly flat, does this imply that we are only working with 2 dimensions? in a 3 dimensional world, flat may just be a conceptual idea.. – bleuofblue Jun 24 '17 at 17:43
• – John Rennie Jun 24 '17 at 18:15
• This is also related – John Rennie Jun 24 '17 at 18:16
• bleuofblue imagine that a nucleus makes a round tube in horizontal direction of radius \delta and imagine that this tube contains all other nucleus of the material. And of course we are working on a 2D instantaneous picture of the atoms ! – Romain B. Jun 24 '17 at 18:35
• What does "flat" mean? Answer that question first. – probably_someone Jun 24 '17 at 18:56

A perfect "flat" surface does not exist and taking q.m. into account is not a meaningful concept. As pointed out by the others, even the radius of an atom is not uniquely defined (e.g. $1/e$ radius, ...).
• First step: Define roughness. Instead of "flatness" people prefer the concept of "roughness", which is the deviation of "flatness". As always, there exists different definitions of roughness, e.g. \begin{align} \textrm{"absolute" roughness value: } R_a &= \sum_j |r_j - \mu| = \sum_j |\delta_j|\\ \textrm{"RMS" roughness value: } R_q &= \sum_j (r_j - \mu)^2 = \sum_j \delta_j^2\\ \end{align} where $\mu = \sum_j r_j$ is the mean value -- instead of sums we should use integrals if $r$ is a continuous variable.
• Second step: Splitting into wavelength. As you pointed out in your question, it is not meaningful to speak about flatness in general. Therefore, we speak of roughness in specific wavelength (or spatial frequency) bands. E.g. it makes perfect sense to speak about a RMS roughness of 1nm in the wavelength band [$1\mu m$ ... $50\mu m$].