In my picture of the quantum computers, the memory would deal with matter in superposition. The matters actual state is said be precisely unknown and you cannot cleary say it is in this state or another, but only to a degree this or to a degree not this. In conventional computers, the memory addresses are either in one of two states this or not this.

My question is this then a quantum computer must have memory states of just fuzzy. This could be described as (1 and 0) if the quantum computers memory is said to be a state of uncertainty all the memory qubits would all be in the same state of fuzziness. How could you then differentiate between the state of each qubit and use this to represent a variety of information? Is it therefore that each qubit's state would have to be in a different degree of uncertainty to another? And with this, would it mean that you could differenciate between qubit's, and use this to represent a variety of information?

Finally then a quantum computer with a finite number of qubit's must have a memory which has an infinite amount of possible states because of the limitless degrees of uncertainty a qubit can be in?


closed as unclear what you're asking by peterh, Jon Custer, Yashas, John Rennie, Void Jun 16 '17 at 8:53

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

  • 2
    $\begingroup$ I am not clear about what you are asking. Please make it clear $\endgroup$ – Lê Dũng Jun 15 '17 at 21:25
  • $\begingroup$ That in order to determine what something is it has to obsevered to be this or that (to be or not to be) surely something that is not clearly defined and in two states at the same time the things description can only be described as fuzzy and vague. $\endgroup$ – 8Mad0Manc8 Jun 15 '17 at 21:31
  • $\begingroup$ I suggest to break up your text into smaller sentences. I wished to fix it, but honestly I simply can't decode where ends a statement and where the next begins. It is like your text had been generated by a spam engine. $\endgroup$ – peterh Jun 15 '17 at 22:39
  • $\begingroup$ @peterh the grammar in my comment or in the question or both. Sorry I find it difficult composing something while using a mobile phone. $\endgroup$ – 8Mad0Manc8 Jun 15 '17 at 22:48
  • 1
    $\begingroup$ If you want your question to be taken seriously given the comments above you'll have to do find a proper keyboard to make appropriate edits. @peterh is absolutely spot on: in its current form near impossible to read. $\endgroup$ – ZeroTheHero Jun 15 '17 at 23:37

First for all, saying it has three possible states is completely wrong as 1 and 0 are also superposition of 0 and 1. And yes, the major problem in quantum computation is that the information is computed in superposition's and we cannot measure the state exactly and there is only a probability of measuring a particular state.But this is also the advantage.

To compute something ,we don't have to apply a gate(like not gate for a bit flip) to each and every bit like in conventional computer but we can just create a superposition of everything we want and then apply the gate once.The nature will take care of the rest.This result in exponential increase in computation.For n bits, the computation power is equivalent to $2^n$ classical bits. Actually, if you have 200 qubit computer, then you have more computational power than whole of the world combined.But making algorithms for quantum computers is different and more difficult.To learn more,you can check our grover's search algorithm and shor's algorithm for prime number factorization.Because the final result correctness is probabilistic,you always have to take care of the errors that will be present.

  • $\begingroup$ I understand that when observing at the quantum level there are degrees of certainty as to the state of something which manifest s in a probability of something's state ie it's position is there but you become more uncertain of where it's going. So does applying the not gate reverse what you observe of the the degree of state of all the $\endgroup$ – 8Mad0Manc8 Jun 15 '17 at 22:32
  • $\begingroup$ The super position of "things" at once $\endgroup$ – 8Mad0Manc8 Jun 15 '17 at 22:34
  • $\begingroup$ I think you should learn a little bit about quantum computing.See wazirani lectures on quantum computing on edx. We don't measure the position and momentum of the qubit simultaneously but just measure, for example the state of polarization in a photon or the energy state of an atom and these act as our qubits. I am not talking about the uncertainity principle here which you seem to be referring to.Also google hadamard gate for quantum computers. $\endgroup$ – Rishabh Jain Jun 15 '17 at 22:47
  • $\begingroup$ Sorry for badgering you but isn't the uncertainty principle responsible for inaccuracies in measurment of the energy state of an atom or photon. Never mind I'll delve into some more thankyou $\endgroup$ – 8Mad0Manc8 Jun 15 '17 at 22:55
  • $\begingroup$ I'll try and explain my self some more when you measure something you get a quantity back but as I understand it this quantity is fuzzy because of the HUP, or is the quantity you measure the exact state of the photon or atom and you needn't worry about the HUP. $\endgroup$ – 8Mad0Manc8 Jun 15 '17 at 23:10

Not the answer you're looking for? Browse other questions tagged or ask your own question.