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I don't really understand the difference and the relation between work and kinetic energy. When you move an object a distance you do work (or does the object work?), what's the object's kinetic energy? Is the kinetic energy the work you've put in to the box all gathered up at the end of the distance given the box keeps moving when you stopped pushing the box? The box can't have kinetic energy if's stationary after I've pushed the box can it?

Sorry if it's unclear.

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  • $\begingroup$ Have you read up the definitions? $\endgroup$
    – gented
    Commented Jun 6, 2017 at 15:29
  • $\begingroup$ Yeah, just didn't really understand them @GennaroTedesco $\endgroup$
    – Iram Haque
    Commented Jun 6, 2017 at 15:34
  • $\begingroup$ What's there to understand? The kinetic energy is defined as $1/2 mv^2$ and the work done by a force along a path is equal to the difference in kinetic enery between the endpoints. $\endgroup$
    – gented
    Commented Jun 6, 2017 at 15:35
  • $\begingroup$ Well, I didn't quite pick that up. @GennaroTedesco $\endgroup$
    – Iram Haque
    Commented Jun 6, 2017 at 15:39

3 Answers 3

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The kinetic energy is indeed the work you have done (assuming no change in potential energy), however this is also neglecting the effect of friction. In real life, the kinetic energy of the box is going to be constant if its moving at a constant velocity even if you are exerting a force on the box and hence doing work on the box. This is because in this case, the work you are doing is being converted into heat and sound due to friction. If we neglect friction, your box would keep accelerating as you applied a force and hence the kinetic energy would keep increasing.

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  • $\begingroup$ So not considering friction, if you've don a certain amount of work on a object, that amount of work is equal to the kinetic energy, correct? $\endgroup$
    – Iram Haque
    Commented Jun 6, 2017 at 15:27
  • $\begingroup$ Yes, although this also assumes there is no change in the potential energy of the object. $\endgroup$ Commented Jun 6, 2017 at 15:39
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Work translates directly into kinetic energy unless there is a potential field or friction. In the case of a potential the energy of work may be shared between kinetic energy and potential energy. When friction is present some or all of the energy of work may go into heating the environment.

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  • $\begingroup$ So it will reduce the kinetic energy but surely the work-energy theorem will apply,right? $\endgroup$ Commented Jan 13, 2018 at 2:34
  • $\begingroup$ On second thought it won't ....got that' $\endgroup$ Commented Jan 13, 2018 at 2:36
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When we move an object, we apply a force. We do not do any work nor does the box do any work. The force does work. The difference between work and energy is that energy is the capacity to do work. You can think of energy as stored work. The relation between work and energy is that the work a force does on an object equals the change in energy, not just kinetic energy but any form of energy. The box cannot have kinetic energy if it is stationary but it acquires kinetic energy when a force does work on it and it continues to be in motion.

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  • $\begingroup$ what happens to energy when it's stationary, it doesn't disappear right? $\endgroup$
    – Iram Haque
    Commented Jun 6, 2017 at 15:29
  • $\begingroup$ You have to do work to stop an object in motion. The sign(positive or negative) of work done to stop an object is opposite to that of the work done to put it in motion while the magnitude remains the same. So, the total work becomes 0. $\endgroup$ Commented Jun 6, 2017 at 15:39
  • $\begingroup$ If we'd consider a particle with no friction, if a force has earlier affected it and right now the particle is stationary, does it still have energy? $\endgroup$
    – Iram Haque
    Commented Jun 6, 2017 at 17:58

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