# What is the relation between a fixed force and work?

How would you translate a constant force into work or energy? If I have a way to output 100KN continuously, how can I translate that into watts? Is there a formula for that translation?

• To do work, you must cause the body upon which you apply the force to move through a distance. In that case, the work done is the force times the distance moved. – Chet Miller Jun 5 '17 at 0:50
• And, since watts is power, the amount of work that was done divided by the time that it took to do that work is the power that was applied. – David White Jun 5 '17 at 1:21
• $E=W=F \cdot d$, $P=W/t$ – Brethlosze Jun 5 '17 at 4:15
• Assuming your object moves at a constant velocity, then from P=FV and by knowing both F and V you can find the power output. – EigenFunction Jun 5 '17 at 7:03
• And remember that all the products you see in the comments above are scalar products of vectors, so you must take either the directions in consideration. – Claudio P Jun 5 '17 at 11:44

A force does work if there is atleast a component of the force in the direction of displacement of the block. The small work done $dw$ by a constant force $f$ in displacing the block through a small displacement $ds$ is given by $dw=fdscos\theta$, where $\theta$ is the angle between the force vector and the displacement vector. Since, power is work done per unit time,that is, $p= \frac{dw}{dt}$ .
That is, $p= fvcos\theta$, , where $\theta$ is the angle between the force vector and the velocity vector.