For a cubic box the energy of a particle is given by:

$$ E = \frac{\pi^2 \hbar^2}{2mL^2} [n_1^2+n_2^2+n_3^2]$$

It is possible that $E$ has the same value for different combinations of $n_1, n_2$ and $n_3$.

I have read that when there are states with the same energy, this energy level is said to be degenerated.

Does this mean that the probability to get this level is $0$?


1 Answer 1


Degeneracy means, an energy-level can be occupied by different combinations of quantum number $n_i$. So you are correct in this point. But this means, there are multiple eigenstates with the same value, so their probability is the same for every eigenstate and not $0$.

A more thorough explanation can be found here.


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.