is there any relation between the emissivity and the temperature?

I was just wondering if there is any relation between the emissivity and the temperature (i.e. temperature as a function of the emissivity).

If yes, can you write the relation and cite a reference for your answer?

Thanks.

$$\epsilon(T)= \frac{E(T)}{E_b (T)}$$ $\epsilon$ is total hemespherical emissivity. $E$ is the emissive power of the actual body which depend on temperature and $E_b$ is the emissive power of a blackbody: $E_b(T)=\sigma T^4$
• @kazekage There's not much more to say here. The particular form of $E(T)$ depends heavily on the particular body you're examining, and may deviate significantly from the usual Stefan-Boltzmann form. – probably_someone Feb 11 '18 at 1:39