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I was just wondering if there is any relation between the emissivity and the temperature (i.e. temperature as a function of the emissivity).

If yes, can you write the relation and cite a reference for your answer?

Thanks.

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Yes emissivity depends on temperature:

$$ \epsilon(T)= \frac{E(T)}{E_b (T)} $$ $\epsilon$ is total hemespherical emissivity. $E$ is the emissive power of the actual body which depend on temperature and $E_b$ is the emissive power of a blackbody: $E_b(T)=\sigma T^4$

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  • $\begingroup$ Can you please explain the terms in more details? $\endgroup$ – kazekage May 3 '17 at 13:09
  • $\begingroup$ @kazekage There's not much more to say here. The particular form of $E(T)$ depends heavily on the particular body you're examining, and may deviate significantly from the usual Stefan-Boltzmann form. $\endgroup$ – probably_someone Feb 11 '18 at 1:39

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