You can evaporate water without boiling it (that’s how clothes get dry!). It will use only latent heat in order to change the phase of the system and won’t heat up water on the process.
How to estimate the energy consumed to evaporate the water without boiling it? How many kJ will be consumed (from the environment, latent heat) by the evaporation of 1 liter of water contained in clothing washed at 40°C put on a drying rack?
According to this page:
https://en.wikipedia.org/wiki/Latent_heat, reference 10, I could estimate that, if the clothing are at 35°C, it would take
2500-2,36*35+0,0016*35*35-0,00006*35*35*35j/g, which is 2416j to evaporate 1g of water. So this would give us 2416kJ for 1 liter of water, so approximately 671kWh (according to google converter).
It's a poor computation and I'm surprised we raise almost 1kWh, which is a lot (I bet some electric dryer may consume less to evaporate 1 liter of water from some clothing...)
Would that be correct?