I'm studying a toy theory in quantum field theory. There are two free fields: a real massive scalar field $\phi$ with mass $M$ and a complex massive scalar field $\Psi$ with mass $m$.
They are coupled by $$ \mathcal{L} \subset g \Psi \Psi^\dagger \phi $$ I'm well aware that this interaction term results in a Lagrangian which is unbounded below, but it's just a toy model I'm using to try to get a grasp on the basics of quantum field theory.
Now, when I go to compute the tree-level scattering amplitude for $\Psi\Psi \to \Psi\Psi$ scattering I end up with a $T$-channel diagram and a $U$-channel diagram. (In both diagrams the two $\Psi$ particles come in, exchange an off-shell $\phi$ particle, and scatter into their final states).
The sum of these two diagrams gives me the total matrix element, which goes like $$ \frac1{(t-M^2)} + \frac1{(u-M^2)} $$ ignoring the factor's of $i$ and the factor of $g^2$. In computing this amplitude I worked in the center of mass/momentum frame, with the initial four momentum of the two particles being $(E(p),0,0,\pm p)$, with the final four momentum of the two particles being $(E(p),0, \pm \cos(θ)p, \pm \sin(θ)p)$. This ensures that four-momentum is conserved.
With this parametrization, $t$ becomes $-4(p\sin(θ/2))^2$, and $u$ becomes $-4(p\cos(θ/2))^2$. Things get interesting in the limit as $M \to 0$, i.e., the mass of the phi particle approaches zero. In this case the scattering amplitude becomes unbounded as $θ$ approaches zero or $\pi$. This is, to my mind, a highly unphysical result.
Is this divergence a result of a fundamental issue with this toy-model? How can we make sense of this result? What is the physical interpretation of a divergent scattering amplitude? Worse still is the fact that the integrated/total cross section also appears to diverge in all of these cases.