enter image description here

In this we have to find work done by the gas .

I thought

work done by gas = work done by spring

work done by gas = $\frac12kx^2$

but my sir told me that I have made some conceptual mistake, I could not understand what ?

  • $\begingroup$ My sir told me the answer as work done by the gas is $5[PV-kx^2 -kxV/S]/2$ $\endgroup$ – search Apr 23 '17 at 14:33


Change in volume of gas $$\Delta V= \text{cross-sectional area of piston}\times \text{change in position of piston}=S\times x_0$$

This is possibly the conceptual part you are missing.

Also, since we are dealing with an ideal gas you may then apply the equation of state.

  • $\begingroup$ See my above comment $\endgroup$ – search Apr 23 '17 at 14:34
  • $\begingroup$ Okay read it, but you have to show your working first. Think about all the energy contributions by the gas. $PV$ is an energy term, so is $\frac{1}{2}kx^2$ etc. $\endgroup$ – BLAZE Apr 23 '17 at 14:38

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.