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In this we have to find work done by the gas .

I thought

work done by gas = work done by spring

work done by gas = $\frac12kx^2$

but my sir told me that I have made some conceptual mistake, I could not understand what ?

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  • $\begingroup$ My sir told me the answer as work done by the gas is $5[PV-kx^2 -kxV/S]/2$ $\endgroup$ – search Apr 23 '17 at 14:33
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Hint:

Change in volume of gas $$\Delta V= \text{cross-sectional area of piston}\times \text{change in position of piston}=S\times x_0$$

This is possibly the conceptual part you are missing.


Also, since we are dealing with an ideal gas you may then apply the equation of state.

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  • $\begingroup$ See my above comment $\endgroup$ – search Apr 23 '17 at 14:34
  • $\begingroup$ Okay read it, but you have to show your working first. Think about all the energy contributions by the gas. $PV$ is an energy term, so is $\frac{1}{2}kx^2$ etc. $\endgroup$ – BLAZE Apr 23 '17 at 14:38

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