In this we have to find work done by the gas .
I thought
work done by gas = work done by spring
work done by gas = $\frac12kx^2$
but my sir told me that I have made some conceptual mistake, I could not understand what ?
$\begingroup$
$\endgroup$
1
-
$\begingroup$ My sir told me the answer as work done by the gas is $5[PV-kx^2 -kxV/S]/2$ $\endgroup$– searchApr 23, 2017 at 14:33
Add a comment
|
1 Answer
$\begingroup$
$\endgroup$
2
Hint:
Change in volume of gas $$\Delta V= \text{cross-sectional area of piston}\times \text{change in position of piston}=S\times x_0$$
This is possibly the conceptual part you are missing.
Also, since we are dealing with an ideal gas you may then apply the equation of state.
-
-
$\begingroup$ Okay read it, but you have to show your working first. Think about all the energy contributions by the gas. $PV$ is an energy term, so is $\frac{1}{2}kx^2$ etc. $\endgroup$– BLAZEApr 23, 2017 at 14:38