Is really the electric field felt in every thing in space? I was wondering if the action/force of the electric field is really felt everywhere. I know it does reduce as you get further, but my thoughts concerned more about materials.
So, I know that the electric field is strictly related to Coulomb's Law, and Coulomb's Law is different between materials. So my questions are,  


*

*Does a net elctric field (generated by two oppositely charged object)
is felt in every material in space? (In the picture, bottles,wood,copper,air,etc..)

*If it does, does it change its intensity based on materials? How?  


I made a picture to try to help you understand my strange question, I drew the electric field reversed, because I like to imagine electrons moving.
If there are problem with the question, please let me know in a comment. I will try immediately to fix them, editing the question
 A: If I understood the question correctly, yes.
Since every material, at least at the scale you seem to be interested, is made up of atoms, which is a collection of (balanced) positive and negative charges, it will "feel" the effects of an electric field, since the charges that constitute the material will "feel" it.
Of course different materials (e.g. different types of atoms and arrangements​) respond differently to the same electric fields. A major distinction is to be made between conductors and insulators (or dielectrics). You can find information between the behaviour of these categories of materials in virtually any resource covering electromagnetism.
A: Look up something called dielectric constant. It's a measure of how the electric field due to a charge is affected when the charge is placed in another medium. The reference, of course, is made with respect to vacuum. 
Vacuum has a dielectric constant $K$=1. While other material media have $K>1$. 
Basically the term $K$ occurs in the denominator of the expression for electric field or force and is useful in determining the relative electric permittivity of a medium. The relative electric permittivity $\epsilon_r$, electric permittivity of vacuum $\epsilon_0$ and the dielectric constant $K$ are related by the expression 

$\epsilon_r=K\epsilon_0$. 

The relative permittivity is a measure of how the electric field/force is affected by the presence of a medium other than vacuum. 
For vacuum, any expression for the electric field will be something like $\frac{1}{4π\epsilon_0} \frac{q}{r²}$ 
For a medium other than vacuum, the expression becomes $\frac{1}{4π\epsilon_r} \frac{q}{r²}$ or 
$\frac{1}{4πK\epsilon_0} \frac{q}{r²}$ 
An example will help. When we say that $K$ is 80 for water, we mean that the electric field or force would be $\frac{1}{80}$ of its value in vacuum. 
