0
$\begingroup$

Why the electric field calculated in a dielectric is equal to the uniform charge density per unit area divided by epsilon-0 (which is the permitivity in space) shouldn't it be divided by another constant?

$\endgroup$
  • $\begingroup$ -1. Not clear what you are asking. What other constant? Please provide more detail about the situation you are asking about and the difficulty you are having. $\endgroup$ – sammy gerbil Apr 4 '17 at 19:06
0
$\begingroup$

Yes. It should be divided by the relative permittivity.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.