Why the electric field calculated in a dielectric is equal to the uniform charge density per unit area divided by epsilon-0 (which is the permitivity in space) shouldn't it be divided by another constant?
$\begingroup$
$\endgroup$
1
-
$\begingroup$ -1. Not clear what you are asking. What other constant? Please provide more detail about the situation you are asking about and the difficulty you are having. $\endgroup$– sammy gerbilCommented Apr 4, 2017 at 19:06
Add a comment
|
1 Answer
$\begingroup$
$\endgroup$
Yes. It should be divided by the relative permittivity.
