# If a resistance of $0$ ohms and $x$ ohms are in parallel does all current pass through the $0$ resistance? [closed]

If a resistance of $0 \Omega$ and $x$ (and $x>0$) are in parallel does all current pass through the $0$ resistance?

For instance in the following circuit: Set variable resistor to o ohms:

I know that current takes the path of least resistance but surely some would still go through the $12$ ohm resistor?

I am asking why no current goes through the higher resistance. If the lower resistance was 1 (from the variable resistor) the current would go through the higher resistor, so why when the lower resistance is 0 does all the current go through it.

## closed as off-topic by Bill N, ZeroTheHero, Jon Custer, Yashas, Kyle KanosMar 17 '17 at 9:38

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "Homework-like questions should ask about a specific physics concept and show some effort to work through the problem. We want our questions to be useful to the broader community, and to future users. See our meta site for more guidance on how to edit your question to make it better" – Bill N, ZeroTheHero, Jon Custer, Yashas, Kyle Kanos
If this question can be reworded to fit the rules in the help center, please edit the question.

• With $R_3=0 \;\Omega$, total resistance including $R_1$ would be $6+0 =6\;\Omega$ – Henry Mar 16 '17 at 14:53
• Think of what voltage you'll see across the 2 parallel resistors, and from that work out the current through R2. – hdhondt Mar 21 '17 at 8:50

## 1 Answer

$14 V, R=(6+0)\Omega=6\Omega$, thus $I=V/R= 14/6 A$. This current will flow through the battery and $R_1$ (and through the ZERO $\Omega$ resistor $R_3$).
No current will flow through $R_2$. The potential difference over $R_2 = 0$.