# How do electric field lines form only open loops? [duplicate]

I understand that this is a consequence of the conservative nature of electric field, but then how does an electric dipole form closed loops?

• the static electric lines do not form closed loop, the charges are singularities of the field lines – hyportnex Mar 12 '17 at 2:15
• Yes, electrostatic field lines don't form closed loops because $\vec{\nabla} \times \vec{E} = 0$, meaning it is a curl-free vector field. This is a property of a conservative vector field, as it can be expressed as the gradient of some function. (In this case, the electric field being $E = -\nabla V$. – vs_292 Jun 21 '17 at 9:16