Building a bronze stature we make a mold and pour in the liquid bronze when the bronze hardens we remove the mold. The mold is made of 3 Kg of steel and the statue has a mas of 1 Kg. The specific heat of bronze is 360 and the specific heat of steel is 165 If we cool the statue and the mold from 500 degrees C by dropping it into a bucket with 10 Kg of water at 20 degrees C what will the final temperature of the water be? (ignore any steam). Specific heat of water is 4186.
So far I have:
(165)(3 kg)(change in temp) + (360)(1 kg)(change in temp) = (4186)(10 kg)(change in temp)
Am I on the right track? Any tips for further help?