The way the question has been written means that you have to make at least one assumption before before you can answer it.
The first thing to say is that if the current has not reached its maximum it must be changing.
What is not clear is whether or not the current started at a maximum and then the circuit was broken (look carefully at the diagram and there is a break in the circuit to the left of the positive terminal of the battery), or the initial current was zero and the current is building to to a maximum value.
So you either have a "discharging" of a LR circuit or a "charging" of a LR circuit both of which will give you exponential type relationships for the current and voltages.
To find these relationships you assume that the imperfect inductor is an ideal inductor with no resistance in series with a $3\; \Omega$ resistor which in turn is in series with a $17 \; \Omega$ resistor and a $200\;\rm V$ battery.
The voltage that you require is the voltage across the ideal inductor with no resistance in series with a $3\; \Omega$ resistor or the voltage of the battery minus the voltage across the $17\; \Omega$ resistor.