# Basic Static Equilibrium of a rigid body

I'm trying to understand static equilibrium in 3-dimensions, but I feel like I should understand it in 2-dimensions first

let's assume we have a rock with inhomogeneous density (black rectangle) with center of mass C

and are hanging it to the roof using two cables and two ball+socket supports, like in the following image:

by definition, ball and sockets supports do not create any momentum-reaction so I would think to simplify the above diagram with the left one in the following image:

but I am sure this is wrong, as it doesn't take into account the position of the off-centered center of mass C of the rock

I think the correct solution should be something like the right one

I can't completely understand how reaction moments Ma and Mb are generated, or how to calculate them

I'm trying to understand how to simplify this problem, I'm also watching youtube videos of static engineering to try to figure this out, but every lecture is about forces and reaction applied directly on the center of mass of a rigid body

what happens if reactions and forces are applied somewhere else on the body itself?

thank you all for your help!

You can find the angles between the three forces by using the geometry of the arrangement which as well as distances $D_1$ and $D_2$ must include the vertical distance between the centre of mass and the top support (ceiling).