# Photoelectric effect in quantum realm

The photoelectric effect is explained as that if a photon of energy more than the work function is absorbed by an electron, the electron will overcome the energy binding material, it is well supported by Bohr's model of atom where an electron can jump to n=$\infty$ provided a photon of required energy is absorbed.

(I am equating the photoelectric electron emission to excitation of an electron from its ground state to n=$\infty$ in Bohr model)

Now as Bohr model is obsolete, How does the uncertainty principle, Hund's rules and probability distribution(which says that an electron ha a non-zero probability of being located at very large distances) deviate or modify or accommodates in photoelectric effect?

Or to put in another way, What is the quantum mechanical explanation of photoelectric effect?

(I would love a simple explanation,understandable to high schooler)

• The first paragraph of your question sums up as your answer, provided your definition of quantum mechanics is not different. – SchrodingersCat Feb 19 '17 at 11:15

$$H \psi = E \psi$$