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How is heat transferred through two separate bodies which are in contact. The collision of the lattices of atoms of the two bodies is a good answer but if there is a net energy transfer then shouldn't there be a net force on the cooler body to which heat is being transferred to? The molecules of the hotter body should collide with the cooler body and lose some energy and thus transfer some momentum to the cooler body.

Is there actually a net force on a body while there is heat transfer through conduction or is this description of heat transfer insufficient/wrong?

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  • $\begingroup$ You say net force, but are you taking into consideration all the possible forces and thus getting net total in one direction? What about friction? Even in a vacuum you'd have to over come an attractive force due to the Van der waals force between the two surfaces.. $\endgroup$ – user273872 Feb 15 '17 at 3:58
  • $\begingroup$ I don't know how much Newtonian mechanics applies here. If it does, then the energy is transfered through collisions between particles in the two substances. By Newton's Third Law, the slower particle (or with lower KE if of different masses) should respond to the faster particle with the same equal-and-opposite force. $\endgroup$ – bpedit Feb 15 '17 at 4:31
  • $\begingroup$ @bpedit So the faster billiard ball will be pushed after a collision with a slower billiard ball back with the same speed? Of course not. $\endgroup$ – HolgerFiedler Feb 15 '17 at 4:37
  • $\begingroup$ i mean that if the bodies were kept on a frictionless surface then would they slide away?{even if the effect is negligible, is it there?} $\endgroup$ – gautam Feb 15 '17 at 4:43
  • $\begingroup$ @HolgerFiedler. Same force does not at all imply same speed. $\endgroup$ – bpedit Feb 15 '17 at 5:27
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On an theoretical level, not taking in account sideway effects, you are right. To modelling it imagine two identical balloons filled with gas of different temperatures. The hotter gas will inflate his ballon more than the gas of the lower temperature. Holding the balloons before filling with a small gap and filling it with the same wight amount of gas, the hooter gas will displace a little bit the other ballon.

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  • $\begingroup$ This is not heat transfer. Fill your balloons apart from one another with your different temperature gases. Now bring them in contact. Will the cold balloon then be forced away fron the hot balloon due to the heat? This is the OP's question applied to your example. $\endgroup$ – bpedit Feb 15 '17 at 5:36
  • $\begingroup$ @bpedit "the hooter gas (ballon) will displace a little bit the other ballon." What is not clear about this analogy? $\endgroup$ – HolgerFiedler Feb 15 '17 at 6:24

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