What would be the capacitance of a shorted parallel plate capacitor?
I have three answers:
Answer 1: Undefined; Because $C=Q/V$ and since $Q=0; V=0 $ Capacitence becomes $0/0$
Answer 2: Infinite; Because $C=A\epsilon/d$ and here $d=0$
Answer 3: Some definite value; Because when shorted my parallel plate capacitor becomes a single conductor of some shape and Capacitance of a single charged plate? is some finite value. One could say but your shorted is not charged. True, but the final expression for capacitance contains neither $Q$ nor $V$. In fact, capacitance depends on the medium and geometrical parameters of the capacitor.
Which one of the above is right? I'm confused.
EDIT: Kindly also tell me why my other answers are wrong.