The photoelectric effect says that the energy of a photon, if greater than the work function of a metal will liberate an electron from it. The additional energy of an electron just gets converted into the kinetic energy of the electron.
Does this mean that a metal undergoing the photoelectric effect doesn't heat up due to it?
One thing I notice is that when I place a slab of metal under the sun, it heats up. I think since the energy of the sunlight is lower than the work function of the metal, it just gets converted into heat? But then you also have radiation pressure. So does the energy get converted into the kinetic energy of the slab? (If the slab is placed in a vacuum and no other forces are acting on it). But if so, what is happening?
To sum it all up, when a beam of light hits a slab of metal, where is the energy going? Does it heat up the metal? What about radiation pressure, does the energy get converted into the kinetic energy of the slab?