I came across this question in an introductory physics course awhile back and I never got over it: "A hydrogen atom has an electron in the n=5 orbit, what is the maximum number of photons that might be emitted so that it decays to the ground state (n=1)?" The answer the professor was looking for was 4 since he was picturing the atom going $5 \rightarrow 4 \rightarrow 3 \rightarrow 2\rightarrow 1$. This sort of answer is how we are taught to think of atomic transitions in introductory physics courses, but I can't imagine its the complete picture. As far as I can tell the only constraints on the system are energy and angular momentum conservation and if you produce pairs of photons with opposite angular momentum you can produce infinitely many photon pairs, and thus infinitely many photons so there is no max number. There are obviously 'selection rules' on these sorts of transitions but they always seem to procede by some dominant process when as far as I can tell there can be higher-order processes that allow many more transitions to occur.

In short: given the full machinery of quantum mechanics, is the answer to the professor's question even finite? Is he right? Or is the number potentially infinite?

Note: I acknowledge this is a exam/HW problem, but from a loooonnnnngg time ago, and I'm looking for the 'real' answer, not the fake introductory answer, if there is a difference.


  • 1
    $\begingroup$ You are right, two-photon and higher emission is possible, however it is suppressed by many orders of magnitude compared to the normal one-photon emission so can usually be neglected. $\endgroup$
    – user2963
    Jun 29, 2012 at 16:56
  • $\begingroup$ I bet one could calculate the probability distribution of the photon number. It might technically have semi-infinite support, but as Zephyr says, it will go to nearly zero above 4 photons. $\endgroup$
    – Colin K
    Jun 29, 2012 at 17:10
  • 1
    $\begingroup$ arxiv.org/abs/0904.0708 might be of interest $\endgroup$ Jun 30, 2012 at 8:59
  • $\begingroup$ If there's only one atom at the beginning, there's only a finite amount of energy, thus producing infinte number of photons is impossible by coservation of energy. Each time a photon is emitted, it takes some energy with it, so atomic energy level gets lower. $\endgroup$
    – Ruslan
    Dec 27, 2013 at 9:00


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Browse other questions tagged or ask your own question.