I am doing just what the OP wonders as I type this.
The lens inside my eye is exactly the correct power to take an object at infinity and form a perfect real, inverted image on the retina of my eye. So I can drive without glasses, and I could answer SE questions using a giant video screen.
Unfortunately, my monitor is small, only about 1 metre away, and quite out of focus.
So I place a converging lens a few inches in front of my eye. This lens forms a virtual image of my monitor at infinity, so the lens of my eye can focus it on my retina. The virtual image of the screen serves as a real object for the lens in my eye.
Consider a person who has surgery to correct for cataracts, and through some strange screw-up has a diverging lens inserted in their eye.
To correct this error, the victim would use a very powerful converging lens in their glasses. This would form a real inverted image somewhere in the victim's eye, between the lens of the eye and the retina.
From a ray point of few, the diverging lens would "unbend" these rays just enough to move the image to the retina.
From a lens formula point of view, the real image formed by the glasses would be a virtual object for the eye lens. The sign convention for the particular version of the lens formula would apply, and the result would be a real inverted image on the retina...