# Finding out acceleration of cylinder after release [closed]

I am facing trouble with the following problem.

A solid cylinder of mass M=5kg rests on two supports of same height as shown.One support is rough and stationary while other is am smooth plank of same mass M=5kg placed on a smooth horizontal surface.Initially $\theta=37 degree and there is no slipping between the cylinder and stationary support.The support is released from rest. The question is to find out the acceleration of cylinder just after release. I drew a free body diagram of the body. Since friction force is the only tangential force acting on the sphere .So$fR=(1/2)mR^2( a/R)$where$a$is the acceleration of the cylinder.This gives$f=ma/2$.Also since one of the block is stationary.The component of forces along that direction should reduce to zero.So resolving forces in the perpendicular direction we get $$mgcos(\theta)-N_1sin(2\theta)-f=ma$$.All things are known except for$ N_1$.I am facing trouble in finding out$N_1\$ in terms of the acceleration of the cylinder.Any hint to go ahead will be highly appreciated.Thanks.

## closed as off-topic by John Rennie, Bill N, sammy gerbil, Jon Custer, AccidentalFourierTransformJan 20 '17 at 9:32

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