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Given the following events are simultaneous can multiple photons "add" together to give the energy required to produce a positron, electron pair?

$$ h\nu = m_e c^2 \gamma(v_1) + m_e c^2 \gamma(v_2) $$

This equation seems to suggest if I had more photons it WOULD be able to produce the energy of ~1Mev for electron and positron production.

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    $\begingroup$ Yes, see en.wikipedia.org/wiki/… $\endgroup$ – Luke Pritchett Jan 19 '17 at 15:45
  • $\begingroup$ I've already seen this Wikipedia, but it says only two gamma rays can be used $\endgroup$ – Randomrok and petcaveman Jan 20 '17 at 1:28
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    $\begingroup$ At least two photons is sufficient. You cannot use one on-shell photon to create an e+ e- pair, but either on off-shell photon or more than one photon can do it. $\endgroup$ – Luke Pritchett Jan 20 '17 at 2:00
  • $\begingroup$ In the case of lower energy photon $\endgroup$ – Randomrok and petcaveman Jan 1 '18 at 14:10
  • $\begingroup$ *photons, if lower momentum was consequential, would particles still form? v≠0, so mass decreases but the momentum must approach that of the constituent photons. This agrees with debroglies description of a particle. Interesting $\endgroup$ – Randomrok and petcaveman Jan 1 '18 at 14:17

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