Pair production from photons

Given the following events are simultaneous can multiple photons "add" together to give the energy required to produce a positron, electron pair?

$$h\nu = m_e c^2 \gamma(v_1) + m_e c^2 \gamma(v_2)$$

This equation seems to suggest if I had more photons it WOULD be able to produce the energy of ~1Mev for electron and positron production.

• Yes, see en.wikipedia.org/wiki/… – Luke Pritchett Jan 19 '17 at 15:45
• I've already seen this Wikipedia, but it says only two gamma rays can be used – Randomrok and petcaveman Jan 20 '17 at 1:28
• At least two photons is sufficient. You cannot use one on-shell photon to create an e+ e- pair, but either on off-shell photon or more than one photon can do it. – Luke Pritchett Jan 20 '17 at 2:00
• In the case of lower energy photon – Randomrok and petcaveman Jan 1 '18 at 14:10
• *photons, if lower momentum was consequential, would particles still form? v≠0, so mass decreases but the momentum must approach that of the constituent photons. This agrees with debroglies description of a particle. Interesting – Randomrok and petcaveman Jan 1 '18 at 14:17