All the other answers that lenses do show chromatic aberration are perfectly true, but usually they do not show it to anything like the same degree as a prism. This it's because prisms are typically operated with light at much higher incidence angles to their interfaces than for lenses. For an incidence angle of $\theta$, the refraction or angular deviation wrought by the interface is, from Snell's law:
$$\Delta\theta=\arcsin\left(\frac{n_2}{n_1}\sin\theta\right)-\theta$$
So that a change in that deviation owing to a wavelength induced refractive index shift is:
$$\mathrm{d}_{r_n} \Delta\theta =\frac{\sin\theta}{\sqrt{1-r_n^2\,\sin^2\theta}}$$
Where $r_n=n_2/n_1$ and this quantity increases with incidence angle, especially if total internal reflexion is approached.
At least one of the incidence angles in a prism is of the order of $45^\circ$; one seldom allows an angle anything like as high as this in lens design. The reason for this is that spherical aberration is roughly caused by the nonlinearity in Snell's law; if Snell's law were $\theta_1/\theta_2=n_2/n_1$, then spherical lenses would truly focus rays to a point.
Whenever one has severe refraction in lens design, one adds a great deal of aberration which must be nulled elsewhere in the lens system; one thus tends to end up with finely balanced differences of large aberrations and the design becomes exquisitely sensitive to the positioning of lens elements. Thus one only ever sees it in applications where high optical powers in few surfaces are needed and the cost justifies someone's hand tweaking of lenses as the system is built. Typically in miniaturized, high cost optics like microscope objectives.
As John Rennie says, the stacking of different materials can compensate for chromatic aberration. A spherical surface with different materials either side will be converging at wavelengths where the refractive index on the side of the center of curvature is greater than the other, diverging at wavelengths when this side's index is the lesser of the two and the surface yields no power at the wavelength where the two indices are equal. Thus one can choose such surfaces to offset the wavelength dependent optical power elsewhere in the system. "Achromatic"systems bring two wavelengths to a common focus ( usually at either end of the visible spectrum) , apochromats bring three wavelengths to a common focus and I have in the past designed a system bringing seven wavelengths to a common focus. Needless to say, that was a highly specialized application.