Why is the Higgs VEV called vacuum Higgs condensate? In this Lubos says that Higgs VEV is also called vacuum Higgs condensate which the term used by Prof. Englert in this video. Since the Higgs field is bosonic, I wonder whether this terminology has anything to do with Bose-Einstein condensate or condensation (which occurs in a dilute gas of bosons very close to absolute zero). This answer too by Maimon suggested something similar. Can one explain the similarity and connection of BE condensate and the VEV of Higgs?
Does it mean that the electroweak phase transition is related to the BE condensation of the Higgs field?
A similar question was previously asked here.
 A: You learned in school that condensation is a gas or vapour cooling to form a liquid, an example of what physicists call a phase transition. Field theory and particle physics use "condensation" to refer to energy-lowering phase transitions, but that's all BEC and Higgs condensation have in common. In BEC, particles' mutual state is determined by energy minimisation. In Higgs condensation, energy minimisation determines the amplitude but not phase of the Higgs field, and the amplitude is nonzero. This signifies two things, spontaneous symmetry breaking and tachyon condensation. The Higgs potential may be written as $V=-M^2|\phi|^2+\frac{\lambda}{2}|\phi|^4$. The term "tachyon" reflects the negative quadratic term coefficient, but the term is misleading because after quantization no tachyons (particles of negative squared mass) result because $\frac{\partial^2 V}{\partial \phi \partial \phi^\ast}$ lacks negative eigenvalues.
A: I think VEV and condensate terms are quite similar. BEC condensate is just about particles but Higgs VEV is about fields, but they are all about setting to the lowest energy possible for the system. You can see BEC condensate but VEV of fields are much more indirect. 
