An arrow is fired from a height of 65 m above the ground at an angle of 60 degrees above the horizontal. It hits the ground 210 m away from its firing point. Calculate its initial and final velocity, flight time and maximum height.
What I've done so far: Set the origin at the starting point of the arrow, down is the negative-$y$ direction.
$\Delta x = 210 $ m
$\Delta y = -65$ m
So according to the projectile motion formulas:
$v_y^2 = u_y^2 + 2(-9.8)(-65)$
$-65 = u_yt + 0.5(-9.8)t^2$
$210 = u_xt$
I dont know where to go from here