# Movable objects in collisions (car crashes)

I have just finished driving school and received my driver's license. While on the theory classes, we learned that when the speed increases to double the former speed, the energy increases to 4 times the former energy ($E_k=\frac{1}{2}mv^2$ I assume).

There was this scale, which showed how much an object would weigh if I was driving $80 \frac{km}{h}$. I can't seem to figure out how to count the weight in this situation, as I don't even know where to start. Is it impulse, $p=mv$ or what? I read the other answers and they weren't elaborate enough for me (as I have not studied neither English or physics for too long).

That would be given by $$F\Delta t=m\Delta v$$ which, when you divide by $\Delta t$, becomes $$F=ma$$
• Thanks. This is what I thought that it was all about. The scale only specified that the impact was at $80 \frac{km}{h}$ and nothing else was said about the conditions. Dec 20 '16 at 19:31