# How do we actually measure the temperature of a BEC?

I guess quite some people here are familiar with Bose-Einstein condensates (BEC) and their properties. We know that the necessary temperature for condensation is given by $$T_C \simeq 3.3125 \frac{\hbar^2 n^{2/3}}{m k_B}$$ Now, the first ''pure'' BEC was created by cooling Rb-87 down to below about 170 nK using a combination of laser cooling and evaporative cooling (as per Wikipedia).

My question is: obviously, once you've achieved condensation, you know you're below your critical temperature, but can you actually measure any temperature in that regime, e.g. could a research group say "we measured a temperature of 105 nK for our BEC, well below the required 170 nK".

Because reading out temperature with any kind of e.g. a laser system would heat up the sample and falsify the data or even heat the BEC up over $T_C$, right?

• This is a good question. However on a more basic level, you should understand that most standard techniques to measure properties of a BEC involve first completely destroying the system. So what you are really measuring are properties of the preparation procedure, not of the individual systems. This is ok as long as you don't mind repeating the preparation procedure for each measurement you want to make. Of course similar considerations apply to measuring any property of a quantum system. – Mark Mitchison Dec 14 '16 at 16:25
• I get that the "fragility" will be a hindrance in measuring, but being able to consistently prepare the system over and over can overcome many of those problems. But my question still stands: how can I do a temperature readout without feeding energy into the system and thus heating it up? Do I need to know the amount of energy my "thermometer" puts in and subtract that from my measured value? – John W. Dec 14 '16 at 16:34
• I will write up a more detailed answer later, but there are various ways to measure the "temperature" (not strictly a temperature since experimental BECs are energetically isolated). The most common way is to simply switch off the trap and let the cloud freely expand, and then image the density distribution after a certain time of flight. This basically tells you about the momentum distribution before the trap switch-off, hence the temperature (assuming you know the energy spectrum). This method has actually been used down to about 1 nK. But in general, thermometry of cold atoms is very hard. – Mark Mitchison Dec 14 '16 at 16:40
• @MarkMitchison I hope you can find the time. It sounds like exactly the kind of "too easy" solution that makes for elegant experiments. – dmckee Dec 15 '16 at 1:23
• Hey @JohnW. I have started writing it up but of course was distracted by various festivities. It's on the to-do list for sure. – Mark Mitchison Jan 3 '17 at 14:55

As an example of how this all works, near $Tc$ there will be a significant portion of the gas that is still not in the condensate, and forms a broad thermal background. Images of the gas after an expansion period will show a density distribution like the famous Nobel pictures:
For the left two panels, which are at high and intermediate temperature, you can see the broad background which is almost completely replaced by the narrow condensate in the rightmost picture. This broad background just follows the usual Maxwell distribution of velocities, so if you can see it you can use it to determine the temperature (ignoring the central spike of the condensate). However, far below $T_C$ it will be too small to detect, and it is necessary to determine the temperature by another means.