Is it wrong to say that the medium of a photon is his electromagnetic field? Without any air there can't be any soundwaves propagating because the air is the medium for soundwaves. Analogous a photon can't propagate without a EM-field because a photon is the vibration of this field. So can the field be the medium? And perhaps it would be possible for all particles and their fields?
If not why not?
Sean Carroll explaining that fields are real: 1:28:12
https://www.youtube.com/watch?v=gEKSpZPByD0
 A: When you deal with photons, you have to think that, as countTo10 said, they are excited states of the electromagnetic field. So what actually propagates in the space is the EM field, while photons are "delocalized over all the space covered by the field. As an example, think of a 1D standing wave, the frequency of which is $\nu$: given the boundary condition for $\vec E$, $\vec E(x=0,t)=\vec E(x=L,t)=0$, you can say that the wave exists only in the region of space between 0 and L. This means that the photons of frequency $\nu$ are not localized in some point x, instead the are spread over all the region of space from 0 to L. In analogy, a travelling EM wave, the photons are delocalized over all of the wave, thus it's misleading talking about their propagation. 
EDIT
You can think of the EM field as an "entity" that exists even in the absence of charges that can produce EM waves.Now,if an EM wave is produced, it certainly carries some amount of energy, so it is propagated in the space; but when you give a quantum mechanical description of electromagnetism, you deal with photons, that are quanta of energy. They don't "exist" in the real space, but are particles existing in the so-called Foch-space, that is introduced in the second quantization. Notice that actually the quantity that you can measure are the electric and magnetic field, not the number of photons, and that the EM wave is not the wave function of the photons. This is because photons arise when you can notice that the electric and magnetic fields oscilattion are formally equivalent to the position-momentum coordinates of an armonic oscillator. Thus the photons are the quanta of energy derivable from an hamiltonian proper of a quantum mechanical armonic oscillator of position $\hat q \propto \hat E$ and momentum $ \hat p \propto \hat H $. But these coordinates are not real positions and momenta, they just are formally idantical. In this sense the photons are not moving in the real space.
