Consider a gas spring in the vertical 90 degree position and a 275lb weight sitting on the top of it. There is a downward force canceling out an upward force. Now consider we slide out the base 1 degree assume the shock cannot fall over.
Using Trigonometry I calculate using the sine function I use a right triangle configuration with 275 being my Y component force and solving the sine equation I calculate (R)Hypotenuse as being 275/(Sin89) I get 275.042=R.
My question is why is the force calculated greater? I would think the y-component force against the weight will now be less than 275 (275-.042) and the R-component force would be 275.042-275=.042.
More information I probably didn't do a good job of setting up this question. Imagine an automotive floor jack holding a 275lb weight. now replace the hydraulic piston with a gas spring and lets say the spring is at 90 degrees to the floor to start. At this point the spring is supporting the weight and we are in balance. I want to calculate the force on the spring as the bottom of the spring is pivoted outward from under the weight in one degree increments. Essentially the spring is moved from a vertical position to a horizontal position. Each time the spring is moved it is replaced with a spring that has enough force to keep the weight balanced. My thinking is that the spring will be 275 on vertical and zero when it is laying down and the weight is on the floor. In summary I was trying to come up with a formula to plug into an excel spread sheet to show the amount of force on the spring at each degree of increment. Hope this helps.