# Heisenberg Uncertainty Principle and Telescopes

I've heard an analogy on the news regarding the Webb telescope. It said Webb's resolution is such that it would be able to locate from Earth a bumble bee on the moon. I understand that it will be a spaced based telescope, and it will never view the moon from Earth. My question is: will the Uncertainty Principle be violated with this telescope? I must confess I can't do the math, and I do not expect anyone else to do it for me. But what are your thoughts regarding the tremendous resolution of the telescope and the Uncertainty Principal. Am I way off-base on this?

In more detail, the Heisenberg uncertainty principle is nothing more than a relationship between the central second moments of distributions that are Fourier duals of each other. Take the Heisenberg uncertainty principle: $$\sigma_p \sigma_x \ge \frac{\hbar}{2}$$ now square both sides and divide by $\hbar^2$ to get: $$\sigma_k^2 \sigma_x^2 \ge \frac{1}{4},$$ where the wave number is defined as $\mathbf{k} = \mathbf{p}/\hbar$. Go read the proof of the Heisenberg uncertainty principle on Wikipedia - it's derived entirely using the properties of Fourier transforms. The only difference is whether you introduce an unnecessary scaling of $\hbar$ to the wave number.