1
$\begingroup$

The geodesic equation parametrized by the proper time contains two terms:

$$ {d^{2}x^{\mu } \over ds^{2}}=-\Gamma ^{\mu }{}_{{\alpha \beta }}{dx^{\alpha } \over ds}{dx^{\beta } \over ds}\ $$ The dimensions of the different elements of the previous expresion are

$$ [x^{\mu }]=[s] $$ Both have dimnesion of length. The metric tensor being dimensionless implies the dimensionless of the Christoffel symbols $ \Gamma ^{\mu }{}_{{\alpha \beta }}$ and consequently the left and right sides of the equation of the geodesic have different dimensions. What is wrong?

$\endgroup$

1 Answer 1

0
$\begingroup$

The Christoffel symbols are obtained by differentiating with respect to $x^\alpha$, and since the metric is dimensionless if we write the dimensions we end up with:

$$ \left[{d^{2}x^{\mu } \over ds^{2}}\right] =\left[\frac{d}{dx^\alpha}\right]\left[{dx^{\alpha } \over ds}\right]\left[{dx^{\beta } \over ds}\right] $$

So both sides have dimensions of 1/length.

$\endgroup$
0

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.