# When Beta decay of C-14 happens, why doesn't the Nitrogen atom produced have a positive charge?

When a C-14 atom undergoes Beta decay, the Nitrogen atom produced has 7 protons but only 6 electrons. Why is it not positively charged? I'm baffled.

The reaction is often written as $^{14}_6C \rightarrow {}^{14}_7N + \beta^- + \bar \nu_{\rm e}$ which has a net negative charge on the right-hand side, whereas it should be written as $^{14}_6C \rightarrow {}^{14}_7N^+ + \beta^- + \bar \nu_{\rm e}$ to balance charges.
When doing energy calculations when the relative atomic masses are given the mass of $^{14}_7N^+ + \beta^-$ is taken to be the mass of a neutral nitrogen atom as the binding energy of an election in an atom (~eV) is much less that the of the energies involved in the nuclear decay process (~MeV).