Why is electric field lines away from (+) and toward (-)? I have a questions about the electric field lines.

Well in the basic learning, we know that:


*

*The electric field lines extend away from a positive charge

*They move forward a negative charge


Let's take parallel plates, which make a uniform electric field.If we take the basic learning, which I mentioned, in accounts, it's very easy to understand that this is the direction of a positive charge object if we put the object between the plate (move away the positive charged plate and toward negatively charged plate).
The problem is if we put a negative charged object between. Isn't the electric field reversed ?
 A: The direction of the field is defined to be the direction of the force on a positively charged test particle. Positive charges always move away from other +ve charges and towards -ve charges.
As @Charlie says, it is a convention, like driving on the right (or left), or which pin on a plug is "live". So that everyone can agree on the result of a calculation, we all have to define it the same way. It could be defined the other way round, but it isn't. And we can't have both - that would be confusing.
A: The electrostatic field is a smart way to work with the Coulomb's law. We know that a charge $Q$ located in $P$ will produce a force $\textbf{F}_e = \frac{Qq}{4\pi\epsilon_0\|\textbf{PM}\|^3}\textbf{PM}$ on a charge $q$ located in $M$. However, this expression of $\textbf{F}_e$ is not very convenient when you work with a continuous distribution of charges, that's why we prefer to work with what we call the electrostatic field, no more than a mathematical object which facilitate the maths behind physics. We define the electrostatic field created by the charge $Q(P)$ as the field $\textbf{E}(M)$ that, when multiplied by $q$, gives the force of the charge $Q$ on a charge $q$ located in $M$, ie. 
$$\textbf{E}(M) = \frac{Q}{4\pi\epsilon_0\|\textbf{PM}\|^3}\textbf{PM}$$
Using this definition of the electrostatic field, we can notice that it always goes away from positive charges, and toward negative charges.
A field line is defined as a line that is always tangent to the field, and is oriented by the field. Since the electrostatic field is always directed away from positive charges and toward negative charges, field lines must go away from positive charges and toward negative ones.
However, we can't say that field lines are oriented by the motion of any charged object: indeed, as you pointed out, the electromagnetic force acting on a charge $q$ depends on the signe of $q$ since this force is $\textbf{F} = q \textbf{E}$. The electrostatic field doesn't change, it is only the electrostatic force that is reversed by replacing a positive charge by a negative one.
A: It's arbitrary. The physical properties of the "positive" and "negative" charge types play no role. We have chosen to use positive test charges by convention. Why? Because, since the electric field at a point is described by a vector, we can describe things in terms of negative and positive. It turns out that when using the equation $\mathbf{F} = q\mathbf{E}$, where $\mathbf{F}$ and $\mathbf{E}$ are vectors, if $q$ is allowed to be positive or negative, and we think of the test charges in the electric field as being positive, it is easier to understand and talk about the electric field model. Remember that fields are just used as a model, albeit a very helpful and relevant model.
